The difference between outside and inside surface of a cylindrical metallic pipe 14cm long is `44 c m^2` . If the pipe is made of 99cu centimetres of metal, find the outer and inner radii of the pipe.

Explanation

given that `pi(R^2-r^2)h=99cm^3`

so,`(R+r)(R-r)=9/4`.....(1)
`
2pih(R-r)=44cm^2`
so,`(R-r)=1/2`.......(2)
from 1and 2 we have (R+r)`=9/2` and (R-r)`=1/2` after solving we get
R`=5/2cm`
r`=2cm`