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Ratio of moles of Fe (II) oxidised by eq...

Ratio of moles of Fe (II) oxidised by equal volumes of equimolar `KMnO_(4)` and `K_(2)Cr_(2)O_(7)` solutions in acidic medium will be:

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Ratio of moles of Fe (II) oxidised by equal volumes of equimolar KMnO_4 and K_2Cr_2O_7 solutions in acidic medium will be :

Ratio of moles of Fe (II) oxidised by equal volumes of equimolar KMnO_4 and K_2Cr_2O_7 solutions in acidic medium will be :

Ratio of moles of Fe (II) oxidised by equal volumes of equimolar KMnO_4 and K_2Cr_2O_7 solutions in aidic medium will be :

K_(2)Cr_(2)O_(7) in acidic medium coverts into-

The n-factor for K_(2)Cr_(2)O_(7) in acidic medium is

If equal volume of 1M KMnO_(4) and 1M K_(2)Cr_(2)O_(7) solution are used to react with Fe^(2+) oxidized will be :

For a given reductant , ratio of volumes of 0.2 M KMnO_(4) and 1M K_(2)Cr_(2)O_(7) in acidic medium will be

For a given reductant , ratio of volumes of 0.2 M KMnO_(4) and 1M K_(2)Cr_(2)O_(7) in acidic medium will be

Equivalent weights of K_(2)Cr_(2)O_(7) in acidic medium is