" (i) "x=theta+sin theta,y=1+cos theta" at "theta=(pi)/(4)

Find the equation of the tangent to the curve x=theta+sin theta,y=1cos theta at theta=(pi)/(4)

The equation of tangent to the curve x=a(theta+ sin theta), y=a (1+ cos theta)" at "theta=(pi)/(2) is

Find the length of normal to the curve x=a(theta+sin theta),y=a(1-cos theta) at theta=(pi)/(2)

The slope of the normal to the curve x=a(theta-sin theta),y=a(1-cos theta) at theta=(pi)/(2)

Find the equations of tangent and normal to the curve x=a( theta- sin theta), y=a(1 -cos theta)" at "theta=pi//2

The length of normal to the curve x=a(theta+sin theta), y=a(1-cos theta), at theta=(pi)/(2) is

The length of normal to the curve x=a(theta+sin theta), y=a(1-cos theta), at theta=(pi)/(2) is

Find the equation of the tangent line to the curve x = theta + sin theta, y = 1 + cos theta at theta = pi/4

If x =theta -sin theta ,y=1 -cos theta ,then " at " theta =(pi)/(2) ,(dy)/(dx) =

The slope of the nomal to the curve x = a(theta - sin theta), y = a(1-cos theta) at theta = pi/2 is