int log(1+x)^(1+1)

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int (log (1+x))/(1+x) dx on (-1, oo).

Evaluate: underset0overset1 int (log(1+x))/(1+x^2)dx

Evaluate: underset0overset1 int log(1/x-1)dx

int (log (1+(1)/(x)))/(x(1+x))dx=

int_0^1log(1+x)/(1+x^2)dx

Evaluate int(log(1+x))/(1+x)dx on (-1,oo)

Evaluate int_0^1 log(1+x)/(1+x^2)dx

Evaluate the integerals. int (log (1+x))/(1+x)dx on (-1 , oo).

The value of int_0^1 (8 log (1 + x))/(1 + x^2) dx is:

Evaluate the following integrals: underset(0)overset(1)int(log(1+x))/(1+x^2) dx