2x+3y=2;2x-(y)/(2)=(1)/(2)

2x+3y=2,x-(y)/(2)=(1)/(2) .

(x+3)/(2)-y=2,(x-3)/(2)+2y-4(1)/(2) then x=……..

If ((2x-y)/(x+2y))=(1)/(2), then find the value of ((3x-y)/(3x+y))

(x + 2) (x + 1) = (x -2) (x -3) (y+3)(y+2)=(y-1)(y-2)

Solve:(1)/(2(2x+3y))+(12)/(7(3x-2y))=(1)/(2)(7)/(2x+3y)+(4)/(3x-2y)=2 where 2x+3y!=0 and 3x-2y!=0

Find the following products and verify the result for x=-1,y=-2:(3x-5y)(x+y)(2)(x^(2)y-1)(3-2x^(2)y)((1)/(3)x-(y^(2))/(5))((1)/(3)x+(y^(2))/(5))

Let C be the circle with centre (0,0) and radius 3 units.The equation of the locus of the mid points of the chords of the circle C that subtend an angle of (2 pi)/(3) at its center is (A) x^(2)+y^(2)=(3)/(2)(B)x^(2)+y^(2)=1(C)x^(2)+y^(2)=(27)/(4)(D)x^(2)+y^(2)=(9)/(4)