" (sin "(x-pi)+cos(x-pi/2)|*cos(x-2 pi)=

[sin(x-pi)+cos(x-pi//2)]*cos(x-2pi) =___________.

The period of sin(pi/4)x+cos(pi/2)x+cos(pi/3)x is

The period of sin(pi/4)x+cos(pi/2)x+cos(pi/3)x is

(cos(pi-x)cos(-x))/(sin(pi-x)cos(pi/2+x))=cot^(2)x

(cos(pi-x)cos(-x))/(sin(pi-x)cos(pi/2+x))=cot^(2)x

(cos (pi + x) cos (-x)) / (sin (pi-x) cos ((pi) / (2) -x)) = cot ^ (2) x

Prove that: (a) (cos(pi+x) cos(-x))/(sin(pi-x)cos(pi/2+x))=cot^(2)x (b) cos((3pi)/2 + x)cos(2pi+x){cot ((3pi)/2-x)+cot(2pi+x)}=1

( sin x - cos x)^(2) + cos^(2) ((pi)/(4) - x) in

(cos (pi +x) cos (-x))/( sin (pi -x) cos ((pi )/(2) + x))= cot ^(2) x