if A be the area of a triangle, prove that the error in A resulting from small error in the measurement of c is given by `dA=A/4(1/s+1/(s-a)+1/(s-b)-1/(s-c))dc,2s=a+b+c.`

With the usual meaning for a,b,c and s if Delta be the area of a triangle,then the error in Delta,(delta Delta) resulting from a small error in the measurment of c(delta c) is given by

With the usual meaning for a,b,c and s if Delta be the area of a triangle then the error in Delta resulting from a small error in the measurement of c, is

S = 1/2 at^2 where a is a constant. If relative error in measurement of t is y, relative error in measurment of S will be

S = 1/2 at^2 where a is a constant. If relative error in measurement of t is y, relative error in measurment of S will be

Using vectors: Prove that if a,b,care the lengths of three sides of a triangle then its area Delta is given by Delta= sqrt(s(s-a)(s-b)(s-c)) where 2s=a+b+c

Using vectors: Prove that if a,b,care the lengths of three sides of a triangle then its area Delta is given by Delta=sqrt(s(s-a)(s-b)(s-c)) where 2s=a+b+c

If S=(1//2)ab""sinC and alpha is the error in C then, relative error in S is

In DeltaABC,r_1/((s-b)(s-c))=