Electrophilic Addition Reaction

Electrophilic additions reactions proceed in two steps. The first step involves the additions of an electrophile. Name the type of intermediate formed in the first step of the following addition reaction H_(3)C - HC = CH_(2) + H^(+) rarr ?

Electrophillic addition reaction proceed in two steps. The first step involves the addition of an electrophile. Name the type of intermediate formed in the first step of the following addition reaction. H_(2)C-HC=CH_(2)+H^(+) rarr ?

Alkenes are more reactive than alkynes towards electrophillic addition reaction, yet vinyl acetylene reacts with 1 mol of HBr at triple bond. Explain why.

Give reasons for the following: (i) tert-buty lbenzene does not give benzonic acid on treatment with acidic KMnO_(4) . (ii)Normally, benzene gives electrophilic substitution reaction rather than electrophilic addition reaction although it has double bond.

Assertion : CH_(3)-CHBrCH_(3) overset(alc. KOH) underset (Delta)rarr CH_(3)-CH=CH_(2) overset(BrCl)rarrCH_(3)CHClCH_(2)Br Reason : In above reaction product formed is based on the principle of E2 and electrophilic addition reaction by Markownikoff's rule.

The alkenes have pi -bonds which make them highly reactive. These undergo electrophilic addition reactions, Addition of HX to unsymmetrical alkenes gives two products and follow Markovnikov rule and anti- Markovnikov rule. The addition occure through the formation of carbocation in Markovnikov rule and free radicals in anti-Markovnikov zule. The ozonolysis reaction of alkenes helps to locate the position of double bond. Write the major product in the following reaction: CH_(3)- overset(CH_(3))overset(|)CH-CH=CH_(2) overset(HBr)to

The alkenes have pi -bonds which make them highly reactive. These undergo electrophilic addition reactions, Addition of HX to unsymmetrical alkenes gives two products and follow Markovnikov rule and anti- Markovnikov rule. The addition occure through the formation of carbocation in Markovnikov rule and free radicals in anti-Markovnikov zule. The ozonolysis reaction of alkenes helps to locate the position of double bond. Predict the major product in the following reaction: CH_(3)-CH=CH_(2) underset((PhCOO)_(2))overset(HBr)to

The alkenes have pi -bonds which make them highly reactive. These undergo electrophilic addition reactions, Addition of HX to unsymmetrical alkenes gives two products and follow Markovnikov rule and anti- Markovnikov rule. The addition occure through the formation of carbocation in Markovnikov rule and free radicals in anti-Markovnikov zule. The ozonolysis reaction of alkenes helps to locate the position of double bond. Name the products formed when 2-methylpropene is treated with ozone followed by Zn, H_(2)O .

Alkenes and alkynes are unsaturated hydrocarbons and undergo electrophilic addition reactions. In alkenes, the addition occurs in one step while in alkynes the addition occurs in two steps. Alkenes show geometrical isomerism but alkynes do not. Alkynes are more acidic than alkenes which are more acidic than alkanes. Both alkenes and alkynes can be prepared by the electrolysis of sodium or potassium salts of carboxylic acids. Write the major product of the reaction : (CH_(3))_(3)C-CH=CH_(2)overset(HBr)to

The alkenes have pi -bonds which make them highly reactive. These undergo electrophilic addition reactions, Addition of HX to unsymmetrical alkenes gives two products and follow Markovnikov rule and anti- Markovnikov rule. The addition occure through the formation of carbocation in Markovnikov rule and free radicals in anti-Markovnikov zule. The ozonolysis reaction of alkenes helps to locate the position of double bond. What product is obtained when propene reacts with CI_(2) in the presence of water?