cot^(-1)(n)/(pi)>(pi)/(6),n in N

If cot^(-1)(n)/(pi)lt(pi)/(6),ninN then find the maximum value of n

If cot^(-1)(n/(pi))lt(pi)/(6),ninN then find the minimum value of n

If "cot"^(-1)n/(pi)gt(pi)/6n in N then the maximum value of n is

If cot^(-1)""n/pi gt pi/6, n in N , then the maximum value of n is

If cot^(-1)((n^(2)-10n+21.6)/(pi))gt(pi)/6, n in N then n can be

If 4cos theta-3sec theta=2tan theta then theta= (A) "n pi+(-1)^(n)(pi)/(10),,,n in z],[" (B) "n pi+(-1)^(n)(pi)/(6),n in z],[" (c) "n pi-(-1)^(n)(3 pi)/(10),n in z],[" (D) "n pi,n in z]]

If cot theta-tan theta=sec theta, then theta is equal to 2n pi+(3 pi)/(2),nZ b.n pi+(-1)^(n)(pi)/(6),nZ c.n pi+(pi)/(2),nZ d.none of these

If cot^(-1)((n^(2)-10n+21.6)/pi) gt pi/6, n in N , then n can be

The roots of the equation cot x-cos x=1-cot x cos x are(1)n pi+(pi)/(4),n in I(2)2n pi+(pi)/(4),n in I(3)2n pi+-pi or n pi+(pi)/(4),n in I(4)2n pi+pi or (4n+1)(pi)/(4),n in In pi,n in I