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The copper wire, when bent in the form of a square, encloses an area of 484 `c m^2` . If the same wire is bent in the form of a circle, find the area enclosed by it.

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Side of the square `=sqrt(484)m=22m`
Circumference of the circle `=` perimeter of square `=(22xx4)m=88m`
`implies2xx22/7xxR=88impliesR=(88xx7/44)=14m`
Area of the circle `=piR^(2)=(22/7xx14xx14)m^(2)=616m^(2)`.
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