In a circle of radius 6cm, a chord of length 10cm makes an angle of `110^0` at the centre of the circle. Find: the circumference of the circle the area of the circle the length of the arc AB, the area of the sector OAB

Explanation

Given: r=6 cm and length of chord=10 cm and `theta = 110^0`

Circumference of the circle = `2 xx pi xx r = 2xx(22/7)xx(6) = 37.71 cm `

Area of the circle =` pi xx r^2 = (22/7) xx (6)^2 = 113.14 cm^2 `

Length of the arc AB = ` (theta)/(360^0) xx 2 xx pi xx r `

Length of the arc AB =`((110^0)/(360^0)) xx 2 xx (22/7) xx 6 = 11.52 cm`

Area of the sector OAB = `(theta)/(360^0) xxpi xx r^2 `

Area of the sector OAB = `((110^0)/(360^0)) xx(22/7) xx (6)^2 =34.57 cm^2`