In a circle of radius 21cm, an arc subtends an angle of `60^0` at the centre. Find (i) the length of the arc (ii) area of the sector formed by the arc. `(U s epi(22)/7)`

Explanation

Given : radius r= 21 cm and `theta = 60^0`

(i) The length of the arc` = (theta/(360^0)) xx 2pir`

`:.`The length of the arc` = ((60^0)/(360^0)) xx 2 xx (22/7)xx 21 = 22 cm`

(ii) Area of the sector formed by the arc =` (theta/(360^0)) xx pir^2`

`:.`Area of the sector formed by the arc =`((60^0)/(360^0))xx (22/7)xx (21)^2 = 231 cm^2`