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An infinite, uniformly charged sheet wit...

An infinite, uniformly charged sheet with surface charge density `sigma` cuts through a spherical Gaussian surface of radius `R` at a distance `X` from its center, as shown in the figure. The electric flux `Phi` through the Gaussian surface is .

A

`(pi R^(2) sigma)/(epsi_(0))`

B

`(2 pi(R^(2) - x^(2))sigma)/(epsi_(0))`

C

`(x (R-x)^(2) sigma)/(epsi_(0))`

D

`(x(R^(2) - x^(2))sigma)/(epsi_(0))`

Text Solution

Verified by Experts

The correct Answer is:
D

Area of sheet Gaussian surface `=pi (R^2-x^2`
Charge `=sigma pi (R^2-x^2)`, Flux `=(q_(in))/e_0=(sigma pi (R^2-x^2))/e_0`
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