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An infinite sheet of charge has surface ...

An infinite sheet of charge has surface charge density `sigma` . The separation between two equipotential surfaces, whose potential differ by V is:

A

`(sigma V)/( 2 in _(0))`

B

`(2 in_(0) V)/( sigma)`

C

`( in_(0)V)/(sigma)`

D

`(2 sigma in_(0))/(V)`

Text Solution

Verified by Experts

The correct Answer is:
B

`V= sigma/(2e_0).d implies d=(2V e_0)/ sigma`
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Knowledge Check

  • An infinite sheet of charge has a surfaces charge density of 10^-7C/m^2 . The separation between two equipotential surfce whose potentials differ by 5 V is

    A
    `0.64cm`
    B
    `0.88mm`
    C
    `0.32cm`
    D
    `5xx10^-7m`
  • Nature of equipotential surface for a point charge is

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    ellopsoid with charge at foci
    B
    sphere with charge at the centre of the sphere
    C
    sphere with charge on the surface of the sphere
    D
    plane with charge on the surface
  • Electric field intensity at a point due to an infinite sheet of charge having surface charge density sigma is E .If sheet were conducting electric intensity would be

    A
    `E//2`
    B
    `E`
    C
    `2E`
    D
    `4E`
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