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A proton a deutron and an alpha particle...

A proton a deutron and an `alpha` particle are accelerated through potentials of `V, 2V` and `4V` respectively. Their velocity will bear a ratio

A

`1 : 1: 1`

B

`1: sqrt(2) : 1`

C

`sqrt(2): 1: 1`

D

`1: 1: sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
If a charge q is accelerated through a p.d. of V volts then velocity v is given then
`1/2 mv^2= qv implies v=sqrt((2qV)/m) implies v_p: v_d: v_a =sqrt((2 eV)/m), sqrt((2e(2v))/m), sqrt(((2e)(4v))/(4m)), 1:1 sqrt2`
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