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Charges +q and -q are placed at points A...

Charges `+q` and `-q` are placed at points `A` and `B` respectively which are a distance `2L` apart, `C` is the midpoint between `A` and `B`. The work done in moving a charge `+Q` along the semicircle `CRD` is

A

`(qQ)/(4 pi epsi_(0)L)`

B

`(qQ)/(2 pi epsi_(0)L)`

C

`(qQ)/(6 pi espi_(0)L)`

D

`-(qQ)/(6 pi epsi_(0)L)`

Text Solution

Verified by Experts

The correct Answer is:
D
Initially

`v_1= (KQ q)/L- (KQ q)/L- (K q^2)/(2L)`
Finally,

`V_f=(kq^2)/(2L)+(2Lq)/(3L)- (KQ q)/L`
Work done =`Delta V= V_f-V_i=- (q Q)/(6 pi e_0L)`
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