Home
Class 12
PHYSICS
Electric field on the axis of a small el...

Electric field on the axis of a small electric dipole at a distance r is `vec(E)_(1)` and `vec(E)_(2)` at a distance of `2r` on a line of perpendicular bisector is

A

`vec(E_(2)) = (-vec(E_(1)))/(8)`

B

`vec(E_(2)) = (-vec(E_(1)))/(16)`

C

`vec(E_(2)) = (-vec(E_(1)))/(4)`

D

`E_(2) = - (vec(E_(1)))/(16)`

Text Solution

Verified by Experts

The correct Answer is:
B
`overline E_1=1/(4 pi e_0) (2 overline p)/r^3` (along `overline p`) , `E_2=-1/(4 pi e_0) overline (p)/(2pi)^3` (Opposite to `overline p`) , So , `overline E_2= overline E_1/16`
Promotional Banner

Similar Questions

Explore conceptually related problems

Electric field_ on the axis of a small electric dipole at a distance r is bar(E_1) and_ at a distance of 2r on a line of perpendicular bisector is bar(E_2) . Then

The electric field and the potential of an electric dipole vary with distance r as

The electric field and the potential of an electric dipole vary with distance 'r' as

At a far away distance r along the axis from a electric dipole electric field is E. Find the electric field at distance 2r along the perpendicular bisector.

The electric field due to a dipole at a distance on its axis is

If the electric potential on the axis of an electric dipole at a distance 'r' from it is V, then the potential at a point on its equatorial line at the same distance away from it will be

The electric potential in volts due to an electric dipole of dipole moment at a 2 xx 10^(-5)C-m distance of 2m on perpendicular bisector is