Home
Class 12
PHYSICS
A conductor having a cavity is given a p...

A conductor having a cavity is given a positive charge. Then field strength `E_(A) , E_(B)and E_(C)` at point A( within cavity ), at B ( within conducutor but outside cavity ) and C( near conductor and outside ) respectively will be :

A

`E_(A) = 0 , E_(B) = 0 ,E_(C) = 0 `

B

`E_(A)ne 0 , E_(B) = 0 , E_(C) ne 0`

C

`E_(A)ne0 , E_(B) ne 0,E_(C)ne 0`

D

None of the above

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the electric field strength at three different points (A, B, and C) in relation to a charged conductor with a cavity. ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have a conductor with a cavity inside it. - The conductor is given a positive charge. 2. **Electric Field Inside the Cavity (Point A)**: - According to electrostatic principles, the electric field inside a conductor in electrostatic equilibrium is zero. - Since point A is located within the cavity of the conductor, there are no charges present in the cavity. - Therefore, the electric field strength at point A, \( E_A \), is **zero**. \[ E_A = 0 \] 3. **Electric Field Inside the Conductor (Point B)**: - Point B is located within the material of the conductor but outside the cavity. - Again, since the conductor is in electrostatic equilibrium, the electric field inside the conductor is also zero. - Thus, the electric field strength at point B, \( E_B \), is **zero**. \[ E_B = 0 \] 4. **Electric Field Outside the Conductor (Point C)**: - Point C is located outside the conductor. - The positive charge placed on the conductor will distribute itself uniformly on the outer surface of the conductor. - As a result, there will be an electric field present in the region outside the conductor due to this surface charge. - Therefore, the electric field strength at point C, \( E_C \), is **non-zero**. \[ E_C \neq 0 \] 5. **Final Summary**: - The electric field strengths at the three points are: - \( E_A = 0 \) - \( E_B = 0 \) - \( E_C \neq 0 \) ### Conclusion: The electric field strengths at points A, B, and C are: - \( E_A = 0 \) - \( E_B = 0 \) - \( E_C \) is non-zero.

To solve the problem, we need to analyze the electric field strength at three different points (A, B, and C) in relation to a charged conductor with a cavity. ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have a conductor with a cavity inside it. - The conductor is given a positive charge. ...
Promotional Banner

Similar Questions

Explore conceptually related problems

A conductor with a cavity is charged positively and its surface charge density is sigma . If E and V represent the electric field and potential, then inside the cavity

Asseration: A point charge q is placed at centre of spherical cavity inside a spherical conductor as shown. Another point charge Q is placed outside the conductor as shown. Now as the point charge Q is pushed away from conductor, the potential difference (V_(A) - V_(B)) between two points A and B within the cavity of sphere remains constant. Reason: The electric field due to charges on outer surface of conductor and outside the conductor is zero at all points inside teh conductor.

Assertion (A): In a cavity in a conductor, the electric field is zero. Reason (R ): Charges in a conductor reside only at its surface.

the figure shows a charge q placed inside a cavity in an uncharged conductor, Now if na external electric field is switched on

What is the field in the cavity if a conductor having a cavity is charged? Does the result depend on the shape and size of cavity or conductor ?

An ellipsoidal cavity is carved within a perfect conductor. A positive charge q is placed at the centre of the cavity. The points A and B are on the cavity surface as shown in the figure. Then