Two point charges `Q_(1)` and `Q_(2)` are positioned at points I and 2. The field intensity to the right of the charge `Q_(2)` on the line that passes through the two charges varies according to a law that is represented in the figure. The field intensity is assumed to be positive if its direction coincides with the positive direction on the x-axis. The distance between the charges is l.

(a) Find the sign of each charge
(b) Find the ratio of the absolute values of the charges `|(Q_(1))/(Q_(2))|`
(c) Find the value of b where the field intensity is maximum
[(a) `Q_(2)` is negative and `Q_(1)` is positive (b) `((l +a)/(a))^(2)`, (c) `(l)/(((l+a)/(a))^(2//3)-1)]`

Options

A. `+,-`
B. `-,+`
C. `+,+`
D. `-,-`

Answer

A

Explanation

Electric field at (2) tends to `-infty` hence, the charge at (2) should be negative. There is neutral point to the right of charges. This is possible only when the charge at (1) should be positive.
Hence `Q_1` is positive and `Q_2` is negative