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Two point charges Q(1) and Q(2) are posi...

Two point charges `Q_(1)` and `Q_(2)` are positioned at points I and 2. The field intensity to the right of the charge `Q_(2)` on the line that passes through the two charges varies according to a law that is represented in the figure. The field intensity is assumed to be positive if its direction coincides with the positive direction on the x-axis. The distance between the charges is l.

(a) Find the sign of each charge
(b) Find the ratio of the absolute values of the charges `|(Q_(1))/(Q_(2))|`
(c) Find the value of b where the field intensity is maximum
[(a) `Q_(2)` is negative and `Q_(1)` is positive (b) `((l +a)/(a))^(2)`, (c) `(l)/(((l+a)/(a))^(2//3)-1)]`

A

`((a+1)/(a))^(2)`

B

`((1)/(a))^(2)`

C

`((a)/(a+1))^(2)`

D

`((a)/(1))^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
At neutral point `vecE_1=vecE_2`
`1/(4 pi e_0 (a+l)^2) =1/(4 pi e_0) Q_2/a^2 implies Q_1/Q_2 =((a+1)/a)^2`
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