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At distance of 5 cm and 10 cm outwards f...

At distance of `5` cm and `10` cm outwards from the surface of a uniformly charged solid sphere, the potentials are `100 V` and `75 V` respectively. Then:

A

potential at its surface is 150V

B

the charge on the sphere is `(5//3)xx10^(-10)C`

C

the electric field on the surface is 1500 V/m

D

the electric potential at its centre is 225 V

Text Solution

Verified by Experts

The correct Answer is:
A, C, D
`(KQ)/(r+5) =100 & (KQ)/(r+100)=75` r, radius of sphere in cm `implies r=10 cm & Q=5/3 times 10^-9 C`
`E_s=(KQ)/r^2=1500 V/m, V_(center)=3/2 (KQ)/r=225V`
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