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Let P(r)=(Q)/(piR^4)r be the charge dens...

Let `P(r)=(Q)/(piR^4)r` be the charge density distribution for a solid sphere of radius R and total charge Q. For a point 'p' inside the sphere at distance `r_1` from the centre of the sphere, the magnitude of electric field is:

A

Zero

B

`Q/(4pi epsilon_0r_1^2)`

C

`(Qr_1^2)/(4pi epsilon_0R^4)`

D

`(Qr_1^2)/(3pi epsilon_0R^4)`

Text Solution

Verified by Experts

The correct Answer is:
C
`E4 pi r_1^2= (int_0^(r_1) Q/(pi R^4) r4 pi r^2 dr)/e_0 implies E=(Qr_1^2)/(4 pi e_0 R^4)`
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