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Two charges, each equal to q, aer kept a...

Two charges, each equal to q, aer kept at `x=-a` and `x=a` on the x-axis. A particle of mass m and charge `q_0=q/2` is placed at the origin. If charge `q_0` is given a small displacement (ylt lt a) along the y-axis, the net force acting on the particle is proportional to

A

y

B

`-y`

C

`1//y`

D

`-1//y`

Text Solution

Verified by Experts

The correct Answer is:
B
`F_(net)=2F cos theta therefore F_(net) =- (2kq (q/2))/ (sqrt(y^2+a^2))^2. y/sqrt(y^2+a^2)`
[negative sign indicates that net force is acting towards the mean position]
`F_(net) =- (2kq (q/2)y)/(y^2+a^2)^(3//2) implies (kq^2y)/a^3 prop -y`
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