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A particle A of charge 1 mu C is held f...

A particle A of charge ` 1 mu C` is held fixed at a point P in free space . Another particle B of same charge and mass `4 mu g` is kept at a distance of1mm from P .If B is released then its velocity at a distance of 9 mm from P is (Take `(1)/( 4pi epsilon_(0)) =9 xx 10^(9)Nm^(2) C^(-2))`

A

`2.0xx10^3m//s`

B

`1.5xx10^2m//s`

C

`3.0xx10^4m//s`

D

`1.0 m//s`

Text Solution

Verified by Experts

`U_(i)=V_(f)+(1)/(2)mv^(2)," "(9xx10^(9)xx10^(-12))/(10^(-3))=(9xx10^(9)xx10^(-12))/(9xx10^(-3))+(1)/(2)xx4xx10^(-9)xxv^(2)rArrv=6.32xx10^(4)m//s`
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