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An electron of mass m(e ) initially at r...

An electron of mass `m_(e )` initially at rest moves through a certain distance in a uniform electric field in time `t_(1)`. A proton of mass `m_(p)` also initially at rest takes time `t_(2)` to move through an equal distance in this uniform electric field.Neglecting the effect of gravity, the ratio of `t_(2)//t_(1)` is nearly equal to

A

1

B

`(m_(p)// m_(e))^(1//2)`

C

`(m_(n) //m_(p))^(1//2)`

D

1836

Text Solution

Verified by Experts

The correct Answer is:
B
Electrostatic force , `F_(e)=eE` (for both the particles)
But acceleration of electron, `a_(e)=F_(e)//m_(e)` and acceleration of proton, `a_(p)=F_(e)//m_(p)`
`S=(1)/(2)a_(e)t_(1)^(2)=(1)/(2)a_(p)t_(2)^(2)rArrtherefore(t_2)/(t_1)=sqrt((a_e)/(a_p))=sqrt((m_p)/(m_e))`
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