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A positive point charge q is fixed at or...

A positive point charge q is fixed at origin. A dipole with a dipole momen `vec(p)` is placed along the x-axis for away from the orgin with `vec(p)` poiniting along positive x-axis .
(i) If the kinetic energy of the diople when it reachers a distance d from the origin is `( qp)/( 4 pi epsi_(0) d^(n))`, then n is .
(ii) If the force experienced by the charge q at this moment is `(4qp)/(pi epsi_(0) d^(3)), hat(i)` then x is.

Text Solution

Verified by Experts

The correct Answer is:
(i) 2 , (ii) 8
Applying energy conservation principle, increase in kinetic energy of the dipole = decrease in electrostatic potential energy of the dipole.
`therefore ` kinetic enegy of dipoile at distance d form origin
` = U_(1) - U_(f)` or ` KE = 0- (-P.E) = p.E = (phat(i))((1)/(4 pi espi_(0))(q)/(d^(2)) hat(i)) = (qp)/(2 pi epsi_(0))`
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