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In the figure below, the square ABCD is made up of two parts, X and Y.The part X, is formed by a semicircle and line AB. The perimeter of X is 36 cm and perimeter of the shaded part Y is 64 cm. a. Find the perimeter of square ABCD b. Find the area of shaded region Y

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`a+pir=36cm-(1)`
`pir+3a=64-(2)`
subtracting equation 2 from equation 1
3a-a=64-36
a=14cm
`a+pir=36cm`
`pir=22cm`
area of semicircle =`1/2*pir^2=22/2*22/22*7=77cm^2`
...
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