" (xi) "(cos30^(@)-sin20^(@))/(cos40^(@)...

" (xi) "(cos30^(@)-sin20^(@))/(cos40^(@)+cos20^(@))=(4)/(sqrt(3))cos40^(@)cos80^(@)

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Prove that, (cos30^(@) - sin 20^(@))/(cos 40^(@) + cos20^(@)) = 4/sqrt3 cos40^(@) cos 80^(@)

cos 20^(@) cos 40^(@) cos 80^(@)=

sin20^(@)*cos40^(@)+cos20^(@)*sin40^(@)=(sqrt(3))/(2)

(2cos40^(@)-cos20^(@))/(sin20^(@))=?

(2cos40^(@)-cos20^(@))/(sin20^(@))

(2cos40^(@)-cos20^(@))/(sin20^(@))

cos20 ^ (@) cos40 ^ (@) cos80 ^ (@) =

cos20^(@)cos40^(@)cos60^(@)cos80^(@)=

cos20^(@).cos40^(@).cos60^(@).cos80^(@)=1/16

cos20^(@).cos40^(@).cos60^(@).cos80^(@)=1/16

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