A chord 10 cm long is drawn in the circle whose radius is `5 sqrt2` cm. Find the area of both the segments.

Explanation

In △OAB,

`OA^2+OB^2=50+50=100`

`AB^2=10^2=100`

i.e., `OA^2+OB^2=AB^2` which satisfies the Pythagoras theorem.

[X_RD_15_E01_29]


Therefore, `theta=90^@`

Area of minor segment=area of sector-Area of △AOB

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