A chord AB of a circle of radius 10cm makes a right angle at the centre of the circle. Find the area of the major and minor segments (Take `pi=3. 14`).

Explanation

Area of segment APBA = area of sector OAPB−area of ΔOAB

`=theta/360^@×pi*r^2−1/2×OB×OA`
`=90^@/360^@​×22/7​×10×10−1/2​×10×10`
`=550/7​−50=200/7`​
`=28.5 cm^2`

Area of major segment `=pi r^2−28.5=22/7​×10×10−28.5`

`= 2200/7​−28.5=200.5/7`
​
`= 285.5 cm^2`