A chord AB of a circle of radius 10cm subtends a right angle at the centre. Find: area of the minor sector area of the minor segment area of the major sector area of the major segment

Explanation

Area of minor sector OAPB `=theta/360​^@×pi*r^2 `

`=90^@/360^@​×22/7​×10×10`

`=550/7​`

`=78.57 cm^2`

Area of minor sector OAQB `= pi r^2 - 550/7​`

`=22/7​×10×10−550/7`

`= 2200/7​−550/7=235.72`
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Area of segment APBA = area of sector OAPB−area of ΔOAB

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