x=3cos t-2cos^(3)t,y=3sin t-2sin^(3)t

If x=3cost-2cos^(3)t,y=3sint-2sin^(3)t then find dy/dx .

"If "x=3cost-2cos^(3)t,y=3sint-2sin^(3)t," show that"(dy)/(dx)=cott.

x=3cost-2cos^(3)t,y=3sint-2sin^(3)t

Show that the equation of normal at any point ton the curve x=3cos t-cos^(3)t and y=3sin t-sin^(3)t is 4(y cos^(3)t-x sin^(3)t)=3sin4t

Find dy/dx, x=3 cos t-2cos^3t , y=3sint-2sin^3t .

If x =3 cos t-2cos ^(3) t,y =3 sin t- 2 sin ^(3) t,then (dy)/(dx) =

If x = 3 cos t - 2 cos^3 t,y = 3 sin t- 2 sin^3 t, then dy/dx is

Show that the equation of normal at any point t on the curve x=3 cos t - cos^(3) t and y=3 sin t - sin^(3) t is 4(y cos^(3) t-x sin^(3) t) = 3 sin 4t .