If two distinct chords of the ellipse `x^2/a^2+y^2/b^2=2` can be drawn through the point `(a -b)`. each bisectde by the line `x + y = b` then the least integral value `(a/b)^2+6(a/b)` can take is equal to

Chords of the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 are drawn through the positive end of the minor axis. Then prove that their midpoints lie on the ellipse.

Chords of the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 are drawn through the positive end of the minor axis. Then prove that their midpoints lie on the ellipse.

Chords of the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 are drawn through the positive end of the minor axis. Then prove that their midpoints lie on the ellipse.

If the set of 'K' for which two distinct chords of the ellipse (x^(2))/8+(y^(2))/2=1 passing through (2,-1) are bisected by the line x+y=K is [a,b] then (a+b) is…………

If the set of 'K' for which two distinct chords of the ellipse (x^(2))/8+(y^(2))/2=1 passing through (2,-1) are bisected by the line x+y=K is [a,b] then (a+b) is…………

If two distinct chords of a parabola y^2=4ax , passing through (a,2a) are bisected by the line x+y=1 ,then length of latus rectum can be a) 2 b) 7 c) 4 d) 5

If two distinct chords of a parabola y^2=4ax , passing through (a,2a) are bisected by the line x+y=1 ,then length of latus rectum can be a) 2 b) 7 c) 4 d) 5

Chords of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 are drawn through the positive end of the minor axis. Then prove that their midpoints lie on the ellipse.

Statement 1 the condition on a and b for which two distinct chords of the ellipse x^(2)/a^(2)+y^(2)/b^(2)=2 passing through (a,-b) are bisected by the line x+y=b is a^(2)+6ab-7b^(2)gt0 . Statement 2 Equation of chord of the ellipse x^(2)/a^(2)+y^(2)/b^(2)=1 whose mid-point (x_1,y_1) is T=S_1

Statement 1 the condition on a and b for which two distinct chords of the ellipse x^(2)/a^(2)+y^(2)/b^(2)=2 passing through (a,-b) are bisected by the line x+y=b is a^(2)+6ab-7b^(2)gt0 . Statement 2 Equation of chord of the ellipse x^(2)/a^(2)+y^(2)/b^(2)=1 whose mid-point (x_1,y_1) is T=S_1