Home
Class 12
CHEMISTRY
Permanganate (VII) ion, in basic solutio...

Permanganate (VII) ion, in basic solution oxidize iodide ion `I^(-)` to produce molecular iodine `I_(2)` and manganese (IV) oxide `MnO_(2)`. Write a balanced ionic equation to represent this redox reaction.

Text Solution

AI Generated Solution

To write a balanced ionic equation for the reaction of permanganate (VII) ion with iodide ion in basic solution, we can follow these steps: ### Step 1: Write the Skeletal Equation The first step is to write the skeletal equation based on the reactants and products given in the question. **Skeletal Equation:** \[ \text{MnO}_4^- + \text{I}^- \rightarrow \text{MnO}_2 + \text{I}_2 \] ...
Promotional Banner

Similar Questions

Explore conceptually related problems

Write a balanced ionic equation to describe the oxidation of iodide (I^-) in by permanganate (MnO_(4)^(-)) ion in basic solution to yield molecular iodine (l_2) and manganese (IV) oxide (MnO_2) . Strategy : We are given the formulas for two reactants and two prodcts. We use these to write the skeletal ionic equatin. We construct and balance the appropriate half-reactions using the rules just described. Then we add the half -reactions and eliminate common terms.

Permanganate ion reacts with bromide ion in basic medium to give manganese dioxide and bromate ion. Write the balanced ionic equation for the reaction.

The Mn^(3+) ion is unstable in solution and undergoes desproportionation reaction to give Mn^(+2), MnO_(2) , and H^(o+) ion. Write a balanced ionic equation for the reaction.