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Given the standard electrode potentials,...

Given the standard electrode potentials, `K^(+) | K = -2.93 V`,`Ag^(+) | Ag = 0.80 V` , `Hg_(2)^(2+) | Hg = 0.79 V` , `Mg_(2)^(2+) | Mg = -2.73 V` , `Cr_(2)^(3+) | Cr = -0.74 V`. Arrange these metals in increasing order of their reducing power.

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Higher the standard electrode potential, higher will be the reducing power.
:.Increasing order of reducing power is `K^(+ )ltMg^(2+) lt Cr(3+) lt Hg^(2+)_(2)ltAg^(+)`
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