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In the reaction. H(2)S+H(2)O(2) rarr S...

In the reaction.
`H_(2)S+H_(2)O_(2) rarr S+2H_(2)O`

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The correct Answer is:
D
`H_(2)S to S^@` Oxidation, so, `H2_(S)` is R.A., `H_(2)O_(2) to H_(2)O^(-2)` Reduction, so, `H_(2)O` is O.A.
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