Home
Class 12
CHEMISTRY
In the given typical redox reaction : M^...

In the given typical redox reaction : `M^(X+) + MnO_(4)^(-) to MO_(3)^(-) + Mn^(2+) + 1/2 O_(2)` , If one mole of `MnO_(4)^(-)` oxidises 2.5 moles of `M^(x+)` , then the value of x is :

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Identify the oxidation states In the reaction, we have the following species: - \( \text{MnO}_4^{-} \) (permanganate ion) - \( \text{MO}_3^{-} \) (the product containing metal M) - \( \text{Mn}^{2+} \) (manganese ion) - \( \frac{1}{2} \text{O}_2 \) (oxygen gas) We need to determine the oxidation states of manganese in \( \text{MnO}_4^{-} \) and \( \text{Mn}^{2+} \). ### Step 2: Calculate the oxidation state of manganese in \( \text{MnO}_4^{-} \) Let the oxidation state of manganese in \( \text{MnO}_4^{-} \) be \( y \). The equation for the oxidation state is: \[ y + 4(-2) = -1 \] \[ y - 8 = -1 \implies y = +7 \] So, the oxidation state of manganese in \( \text{MnO}_4^{-} \) is +7. ### Step 3: Determine the change in oxidation state In the reaction, manganese is reduced from +7 in \( \text{MnO}_4^{-} \) to +2 in \( \text{Mn}^{2+} \). The change in oxidation state is: \[ 7 - 2 = 5 \] This means that 5 electrons are gained by one mole of \( \text{MnO}_4^{-} \). ### Step 4: Determine the n-factor for \( \text{MnO}_4^{-} \) The n-factor for \( \text{MnO}_4^{-} \) is the number of electrons gained or lost, which we found to be 5. ### Step 5: Set up the equivalence equation According to the problem, 1 mole of \( \text{MnO}_4^{-} \) oxidizes 2.5 moles of \( \text{M}^{x+} \). The n-factor for \( \text{M}^{x+} \) can be expressed as \( 5 - x \) since it is undergoing oxidation from +5 to +x. The equivalence of \( \text{MnO}_4^{-} \) and \( \text{M}^{x+} \) can be set up as: \[ \text{Equivalents of } \text{MnO}_4^{-} = \text{Equivalents of } \text{M}^{x+} \] This gives us: \[ 1 \times 5 = 2.5 \times (5 - x) \] ### Step 6: Solve for x Now, we can solve the equation: \[ 5 = 2.5(5 - x) \] Expanding the right side: \[ 5 = 12.5 - 2.5x \] Rearranging gives: \[ 2.5x = 12.5 - 5 \] \[ 2.5x = 7.5 \] Dividing both sides by 2.5: \[ x = \frac{7.5}{2.5} = 3 \] ### Final Answer The value of \( x \) is **3**. ---

To solve the problem, we will follow these steps: ### Step 1: Identify the oxidation states In the reaction, we have the following species: - \( \text{MnO}_4^{-} \) (permanganate ion) - \( \text{MO}_3^{-} \) (the product containing metal M) - \( \text{Mn}^{2+} \) (manganese ion) - \( \frac{1}{2} \text{O}_2 \) (oxygen gas) ...
Promotional Banner

Similar Questions

Explore conceptually related problems

For the reaction M^(x+)+MnO_(4)^(ө)rarrMO_(3)^(ө)+Mn^(2+)+(1//2)O_(2) if 1 "mol of" MnO_(4)^(ө) oxidises 1.67 "mol of" M^(x+) "to" MO_(3)^(ө) , then the value of x in the reaction is

1mol of MnO_(4)^(-) will oxidise x mole of ferric oxalate in acidic medium, x is -

One mole of MnO_(4)^(2-) disproportionates to yield :