One mole of acidified `K_(2)Cr_(2)O_(7)` in reaction with excess `KI` will liberate …… moles of `I_(2)`

Answer

D

Explanation

`Cr_(2)O_(7)^(2-) + 6I^(-) + 14H^(+) to 2Cr^(3+) + 7H_(2)O + 3I_(2)`