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I^(-) reduces IO(3)^(-) to I(2) and itse...

`I^(-)` reduces `IO_(3)^(-)` to `I_(2)` and itself oxidised to `I_(2)` in acidic medium. Thus, final reaction is

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The correct Answer is:
C
`2I^(-) to I_(2) + 2e^(-)` (oxidation)
`2IO_(3)^(-) + 12H^(+) + 10e^(-) to I_(2) + 6H_(2)O` (Reduction)
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