Assertion :- Equivalent weight of `NH_(3)` in the reaction `N_(2) rarrNH_(3)` is `17//3` while that of `N_(2)` is `28//6`.
Reason :- `"Equivalent weight" =("Molecular weight")/("number of "e^(-)" lost or gained/mole")`

Answer

A

Explanation

Both assertion and reason are true and reason is the correct explanation of assertion.br>`overset(0)(N_(2)) + 6e^(-) to overset(-3)(2N)`
`2 mol NH_(3) equiv 6 mol e^(-) implies`n factor of `NH_3` = 3 `implies` Equivalent weight
Observer that : 1 mol `N_2` `equiv` 6 mol `e^(-)` n factor `N_2 = 6 implies`Equivalent weight `=28/6` .