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Pyrolusite is the main ore of manganese ...

Pyrolusite is the main ore of manganese in which it is present as Its Mn content is determined by reducing it under acidic condition to `Mn^(2+)` with the help of oxalate `(C_(2)O_(4)^(2-))` ion which in turn gets oxidized to `CO_(2)` The analytical determination is carried out by adding a known excess volume of `(C_(2)O_(4)^(2-))` solution to a suspension of the pyrolusite and digesting the mixture on a hot water bath until all the `MnO_(2)` has been reduced. The excess unreacted oxalate solution is then titrated with standardized `KMnO_(4)` solution. Thereby Mn content of ore can be calculated. `KMnO_(4)`solution is also standardized under acidic condition against oxalate ion wherein `MnO_(4)^(-)` ion is reduced to `Mn^(2+)` and `(C_(2)O_(4)^(2-))` ion is oxidized to `CO_(2)`
Q sample containing `MnO_(2)` is treated with HCl liberating `Cl_(2)` The `Cl_(2)` is passed into a solution of KI and `30cm^(3)` of hypo is required to titrate the liberated iodine. What is the percentage of `MnO_(2)` in the sample ?

A

`22.64%`

B

`26.1%`

C

`62.2%`

D

`72.5%`

Text Solution

Verified by Experts

The correct Answer is:
B

`MnO_(2)+4HCItoMnCl_(2)+2H_(2)O+Cl_(2)`
`Cl_(2)+2KIto2KCl+I_(2)`
Reaction involed
`I_(2)+2S_(2)O_(3)^(2-)to2I+S_(4)O_(6)`
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