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8 g of sulphur are burnt to form SO(2), ...

`8 g` of sulphur are burnt to form `SO_(2)`, which is oxidised by `Cl_(2)` water. The solution is treated with `BaCl_(2)` solution. The amount of `BaSO_(4)` precipitated is:

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The correct Answer is:
0.25
`S overset(“O_(2)”)to SO_(2) overset (“Cl_(2)”)to `SO_(4)^(2-)` overset (BaCl_(2))to BaSO_(4)`
1 mole of S will give 1 mole of `BaSO_(4)``:. 8/32 = 1/4 `mole of S will give `1/4` mole of `BaSO_(4)`
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