Following reaction takes place in one step: `2NO +O_(2) + 2NO_(2)` How will the rate of above reaction change if the volume of reaction vessel is reduced to 1/3 rd of original volume? Will there be any change in the order of reaction?

Explanation

To solve the problem regarding the change in the rate of the reaction when the volume of the reaction vessel is reduced to one-third of its original volume, we can follow these steps:

### Step 1: Write the balanced chemical equation
The reaction given is:
\[ 2NO + O_2 \rightarrow 2NO_2 \]

### Step 2: Understand the rate expression
For a reaction, the rate can generally be expressed in terms of the concentrations of the reactants raised to the power of their stoichiometric coefficients. The rate expression for this reaction can be written as:
...