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A first order reaction takes 69.3 minute...

A first order reaction takes `69.3` minutes for `50%` completion. How much time will be needed for `80%` completion:
[Give your answer divide by `80.48`]

Text Solution

Verified by Experts

`t_(1//2)=69.3n` ub
`k =(0.693)/(69.3)=0.01" m in"^(-1)`
`t_(80%)=(2.303)/(k)log""([R_(0)])/([R])`
`=(2.303)/(0.01)log""(R_(0))/((20)/(100)R_(0))=(2.303)/(0.01) xx log 5`
`=(2.303)/(0.01)xx0.6990=160.97` m in =2.68 hrs.
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