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The activation energy for the reaction, ...

The activation energy for the reaction, `2Hi(g) to H_(2)(g) + I_(2)(g)` is 209.5 kJ `moli^(-1)` at 581 K. Calculate the fraction of molecules of reactants having energy equal to or greater than activation energy.

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Fraction of molecules having energy equal to or greater than activation energy
`x=e (-E_(a))/(RT)`
`log x =(-E_(a))/(2.303 RT)`
`log x=-(209.5xx10^(3))/(2.303xx8.314xx581)=-18.8323`
x= antilog (-18.8323) = antilog `(bar(19).1677)=1.47xx10^(-19)`
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