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For the reaction : 2N(2)O(5) rarr 4NO(2)...

For the reaction : `2N_(2)O_(5) rarr 4NO_(2) +O_(2)`, the rate of reaction in terms of `O_(2)` is `d[O_(2)]`/dt. In terms of `N_(2)O_(5)`, it will be :

A

`(-d[N_(2)O_(5)])/(dt)`

B

`(+d[N_(2)O_(5)])/(dt)`

C

`-(1)/(2)(d[N_(2)O_(5)])/(dt)`

D

`-2(d[N_(2)O_(5)])/(dt)`

Text Solution

Verified by Experts

The correct Answer is:
C
Rate `=(d[O_(2)])/(dt)=(-1)/(2)(d[N_(2)O_(5)])/(dt)`
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