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The conversion of A rarr B follows secon...

The conversion of `A rarr B` follows second-order kinetics. Doubling the concentration of `A` will increase the rate of formation of `B` by a factor

A

`1//4`

B

2

C

`1//2`

D

4

Text Solution

Verified by Experts

The correct Answer is:
D
`r=k[A]^(2)`
`r'=k(2[A])^(2)=4 k [A]^(2)=4k`
Since `r'=(-d[A])/(dt) =(d[B])/(dt) =4r`.
`therefore` The rate of formation of B increases by 4 times
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