Home
Class 12
CHEMISTRY
If K(1)= Rate constant at temperature T(...

If `K_(1)=` Rate constant at temperature `T_(1)` and `k_(2)` rate constant at temperature `T_(2)` for a first order reaction, then which of the following relation is correct ?

A

`"log "(k_(1))/(k_(2))=(2.303 E_(a))/(R) ((T_(2)-T_(1))/(T_(1)T_(2)))`

B

`"log"(k_(2))/(k_(1))=(E_(a))/(2.303 R) ((T_(2)-T_(1))/(T_(1)T_(2)))`

C

`"log "(k_(2))/(k_(1))=(E_(a))/(2.303 R) ((T_(1) T_(2))/(T_(2)+T_(1)))`

D

`"log "(k_(1))/(k_(2))=(E_(a))/(2.303 R)((T_(1)T_(2))/(T_(2)-T_(1)))`

Text Solution

Verified by Experts

The correct Answer is:
B

We know `k=Ae^(-E_(a)//RT)` For two different temperatures log `((k_(2))/(k_(1)))=(Ea)/(2.303 R)((T_(2)-T_(1))/(T_(1)T_(2)))`
Promotional Banner

Similar Questions

Explore conceptually related problems

If K_1 is the equilibrium constant at temperature T_1 and K_2 is the equilibrium constant at temperature T_2 and If T_2 gt T_1 and reaction is endothermic then

The activation energies of two reactions are E_(1) & E_(2) with E_(1)gtE_(2) . If temperature of reacting system is increased from T_(1) (rate constant are k_(1) and k_(2) ) to T_(2) (rate constant are k_(1)^(1) and k_(2)^(1) ) predict which of the following alternative is incorrect.

The rate constant 'K' for pseudo first order reaction is

The first-order rate constant k is related to temperature as log k = 15.0 - (10^(6)//T) . Which of the following pair of value is correct ?

Two different first order reactions have rate consants k_(1) and k_(2) "at" T_(1)(k_(1)gtk_(2)) . If temperature is increased form T_(1) "to"T_(2) ,then new consant become k_(3) and k_(4) respeectively. Which among the following relartions is correct

For a given exothermic reaction , K_(p) and k'_(p) are the equilibrium constants at temperatures T_(1) and T_(2) respectively. Assuming that heat of reaction is constant in temperature range reaction is constant in temperature range between T_(1) and T_(2) , it is readily observed that

If the rate constant for a first order reaction is k, the time (t) required for the completion of 99% of the reaction is given by :