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The rate of a gaseous reaction is given ...

The rate of a gaseous reaction is given by the expression `k[A][B]`. If The volume of reaction vessel is suddenly reduced to one-fourth of the initial volume, the reaction rate relative to the original rate will be :

A

`1//10`

B

`1//8`

C

8

D

16

Text Solution

Verified by Experts

The correct Answer is:
D
`r=k[A][B] =(k n_(A) n_(B))/(V^(2))`
Where `n_(A) and n_(B)` are moles of A and B respectively and V is volume.
`r'=(kn_(A) n_(B))/((V//4)^(2))=16 (kn_(A)n_(B))/(V^(2))=16 r, (r')/(r)=16`
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