For a reaction of reversible nature , net rate is `((dx)/(dt))=k_(1)[A]^(2)[B]^(1)-k_(2)[C]`, hence , given reactionis:

Options

A. `2A +(1)/(B) C`
B. `2A-B C`
C. `2A C-B`
D. None of these

Answer

C

Explanation

`R_(f) =k_(1)[A]^(2)`
`R_(b) =k_(2)[B][C]" Net rate "=R_(f) -R_(b) =k_(1) [A]^(2)-k_(2) [B] [C]`